Base | Representation |
---|---|
bin | 100011100001001011010011… |
… | …0100111011110000110100111 |
3 | 1111222012100101211200111020011 |
4 | 1013002112212213132012213 |
5 | 311422214311412134421 |
6 | 3024245052225351051 |
7 | 122543550320443042 |
oct | 10702264647360647 |
9 | 1458170354614204 |
10 | 312423011443111 |
11 | 906029451214a8 |
12 | 2b05980a498487 |
13 | 1054349599a55a |
14 | 57214d6803c59 |
15 | 261bc8d4984e1 |
hex | 11c25a69de1a7 |
312423011443111 has 2 divisors, whose sum is σ = 312423011443112. Its totient is φ = 312423011443110.
The previous prime is 312423011443091. The next prime is 312423011443183. The reversal of 312423011443111 is 111344110324213.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 312423011443111 - 221 = 312423009345959 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (312423011441111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156211505721555 + 156211505721556.
It is an arithmetic number, because the mean of its divisors is an integer number (156211505721556).
Almost surely, 2312423011443111 is an apocalyptic number.
312423011443111 is a deficient number, since it is larger than the sum of its proper divisors (1).
312423011443111 is an equidigital number, since it uses as much as digits as its factorization.
312423011443111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 31.
Adding to 312423011443111 its reverse (111344110324213), we get a palindrome (423767121767324).
The spelling of 312423011443111 in words is "three hundred twelve trillion, four hundred twenty-three billion, eleven million, four hundred forty-three thousand, one hundred eleven".
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