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312423240030017 is a prime number
BaseRepresentation
bin100011100001001011011010…
…0001111011101011101000001
31111222012100222202210220111212
41013002112310033131131001
5311422220243421430032
63024245131033015505
7122543556064422134
oct10702266417353501
91458170882726455
10312423240030017
1190602a5215a1a6
122b059872b54595
131054350115358c
145721518d0821b
15261bca359cbb2
hex11c25b43dd741

312423240030017 has 2 divisors, whose sum is σ = 312423240030018. Its totient is φ = 312423240030016.

The previous prime is 312423240030001. The next prime is 312423240030071. The reversal of 312423240030017 is 710030042324213.

Together with next prime (312423240030071) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 246951450366721 + 65471789663296 = 15714689^2 + 8091464^2 .

It is a cyclic number.

It is not a de Polignac number, because 312423240030017 - 24 = 312423240030001 is a prime.

It is a super-2 number, since 2×3124232400300172 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (312423240000017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156211620015008 + 156211620015009.

It is an arithmetic number, because the mean of its divisors is an integer number (156211620015009).

Almost surely, 2312423240030017 is an apocalyptic number.

It is an amenable number.

312423240030017 is a deficient number, since it is larger than the sum of its proper divisors (1).

312423240030017 is an equidigital number, since it uses as much as digits as its factorization.

312423240030017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24192, while the sum is 32.

The spelling of 312423240030017 in words is "three hundred twelve trillion, four hundred twenty-three billion, two hundred forty million, thirty thousand, seventeen".