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312423240030071 is a prime number
BaseRepresentation
bin100011100001001011011010…
…0001111011101011101110111
31111222012100222202210220120212
41013002112310033131131313
5311422220243421430241
63024245131033020035
7122543556064422242
oct10702266417353567
91458170882726525
10312423240030071
1190602a5215a245
122b059872b5461b
1310543501153601
145721518d08259
15261bca359cbeb
hex11c25b43dd777

312423240030071 has 2 divisors, whose sum is σ = 312423240030072. Its totient is φ = 312423240030070.

The previous prime is 312423240030017. The next prime is 312423240030151. The reversal of 312423240030071 is 170030042324213.

Together with previous prime (312423240030017) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is an emirp because it is prime and its reverse (170030042324213) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-312423240030071 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (312423240030001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156211620015035 + 156211620015036.

It is an arithmetic number, because the mean of its divisors is an integer number (156211620015036).

Almost surely, 2312423240030071 is an apocalyptic number.

312423240030071 is a deficient number, since it is larger than the sum of its proper divisors (1).

312423240030071 is an equidigital number, since it uses as much as digits as its factorization.

312423240030071 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24192, while the sum is 32.

Adding to 312423240030071 its reverse (170030042324213), we get a palindrome (482453282354284).

The spelling of 312423240030071 in words is "three hundred twelve trillion, four hundred twenty-three billion, two hundred forty million, thirty thousand, seventy-one".