Base | Representation |
---|---|
bin | 101101011101110000001… |
… | …111111010100100010011 |
3 | 102001200102112122102111021 |
4 | 231131300033322210103 |
5 | 402142104024210220 |
6 | 10351143403500311 |
7 | 441503446412155 |
oct | 55356017724423 |
9 | 12050375572437 |
10 | 3124324444435 |
11 | aa5022774a17 |
12 | 425621b27697 |
13 | 198812914b1c |
14 | ab30a6caad5 |
15 | 5640e1ab4aa |
hex | 2d7703fa913 |
3124324444435 has 16 divisors (see below), whose sum is σ = 3788116617600. Its totient is φ = 2473511786496.
The previous prime is 3124324444391. The next prime is 3124324444441. The reversal of 3124324444435 is 5344444234213.
It is a cyclic number.
It is not a de Polignac number, because 3124324444435 - 211 = 3124324442387 is a prime.
It is a super-2 number, since 2×31243244444352 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3124324444391 and 3124324444400.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6639631 + ... + 7094599.
It is an arithmetic number, because the mean of its divisors is an integer number (236757288600).
Almost surely, 23124324444435 is an apocalyptic number.
3124324444435 is a deficient number, since it is larger than the sum of its proper divisors (663792173165).
3124324444435 is a wasteful number, since it uses less digits than its factorization.
3124324444435 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 469230.
The product of its digits is 2211840, while the sum is 43.
Adding to 3124324444435 its reverse (5344444234213), we get a palindrome (8468768678648).
The spelling of 3124324444435 in words is "three trillion, one hundred twenty-four billion, three hundred twenty-four million, four hundred forty-four thousand, four hundred thirty-five".
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