312444212231341 has 4 divisors (see below), whose sum is σ = 313186360004284. Its totient is φ = 311702064458400.

The previous prime is 312444212231339. The next prime is 312444212231377. The reversal of 312444212231341 is 143132212444213.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 85895175241225 + 226549036990116 = 9267965^2 + 15051546^2 .

It is a cyclic number.

It is not a de Polignac number, because 312444212231341 - 2¹ = 312444212231339 is a prime.

It is a super-3 number, since 3×312444212231341³ (a number of 44 digits) contains 333 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 312444212231341.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (312444212231141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 371073885840 + ... + 371073886681.

It is an arithmetic number, because the mean of its divisors is an integer number (78296590001071).

Almost surely, 2^{312444212231341} is an apocalyptic number.

It is an amenable number.

312444212231341 is a deficient number, since it is larger than the sum of its proper divisors (742147772943).

312444212231341 is an equidigital number, since it uses as much as digits as its factorization.

312444212231341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 742147772942.

The product of its digits is 110592, while the sum is 37.

Adding to 312444212231341 its reverse (143132212444213), we get a palindrome (455576424675554).

The spelling of 312444212231341 in words is "three hundred twelve trillion, four hundred forty-four billion, two hundred twelve million, two hundred thirty-one thousand, three hundred forty-one".