3125013541433 has 8 divisors (see below), whose sum is σ = 3606804880320. Its totient is φ = 2652062410800.

The previous prime is 3125013541427. The next prime is 3125013541469. The reversal of 3125013541433 is 3341453105213.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 3125013541433 - 2¹² = 3125013537337 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3125013541393 and 3125013541402.

It is not an unprimeable number, because it can be changed into a prime (3125013549433) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2210051303 + ... + 2210052716.

It is an arithmetic number, because the mean of its divisors is an integer number (450850610040).

Almost surely, 2^{3125013541433} is an apocalyptic number.

It is an amenable number.

3125013541433 is a deficient number, since it is larger than the sum of its proper divisors (481791338887).

3125013541433 is a wasteful number, since it uses less digits than its factorization.

3125013541433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4420104127.

The product of its (nonzero) digits is 64800, while the sum is 35.

Adding to 3125013541433 its reverse (3341453105213), we get a palindrome (6466466646646).

The spelling of 3125013541433 in words is "three trillion, one hundred twenty-five billion, thirteen million, five hundred forty-one thousand, four hundred thirty-three".