Base | Representation |
---|---|
bin | 101101011110100000011… |
… | …001110011010011011001 |
3 | 102001202111211211220021102 |
4 | 231132200121303103121 |
5 | 402200232334424424 |
6 | 10351355503521145 |
7 | 441532456422113 |
oct | 55364031632331 |
9 | 12052454756242 |
10 | 3125132342489 |
11 | aa53a780a763 |
12 | 4258085b91b5 |
13 | 198911101901 |
14 | ab385b103b3 |
15 | 5645a0937ae |
hex | 2d7a06734d9 |
3125132342489 has 2 divisors, whose sum is σ = 3125132342490. Its totient is φ = 3125132342488.
The previous prime is 3125132342441. The next prime is 3125132342531. The reversal of 3125132342489 is 9842432315213.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2863090732489 + 262041610000 = 1692067^2 + 511900^2 .
It is an emirp because it is prime and its reverse (9842432315213) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3125132342489 is a prime.
It is not a weakly prime, because it can be changed into another prime (3125132344489) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1562566171244 + 1562566171245.
It is an arithmetic number, because the mean of its divisors is an integer number (1562566171245).
Almost surely, 23125132342489 is an apocalyptic number.
It is an amenable number.
3125132342489 is a deficient number, since it is larger than the sum of its proper divisors (1).
3125132342489 is an equidigital number, since it uses as much as digits as its factorization.
3125132342489 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1244160, while the sum is 47.
The spelling of 3125132342489 in words is "three trillion, one hundred twenty-five billion, one hundred thirty-two million, three hundred forty-two thousand, four hundred eighty-nine".
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