Base | Representation |
---|---|
bin | 101101011110100000011… |
… | …001110011010100000011 |
3 | 102001202111211211220022222 |
4 | 231132200121303110003 |
5 | 402200232334430111 |
6 | 10351355503521255 |
7 | 441532456422203 |
oct | 55364031632403 |
9 | 12052454756288 |
10 | 3125132342531 |
11 | aa53a780a7a1 |
12 | 4258085b922b |
13 | 198911101934 |
14 | ab385b10403 |
15 | 5645a0937db |
hex | 2d7a0673503 |
3125132342531 has 2 divisors, whose sum is σ = 3125132342532. Its totient is φ = 3125132342530.
The previous prime is 3125132342489. The next prime is 3125132342581. The reversal of 3125132342531 is 1352432315213.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3125132342531 - 218 = 3125132080387 is a prime.
It is a super-2 number, since 2×31251323425312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3125132342491 and 3125132342500.
It is not a weakly prime, because it can be changed into another prime (3125132342581) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1562566171265 + 1562566171266.
It is an arithmetic number, because the mean of its divisors is an integer number (1562566171266).
Almost surely, 23125132342531 is an apocalyptic number.
3125132342531 is a deficient number, since it is larger than the sum of its proper divisors (1).
3125132342531 is an equidigital number, since it uses as much as digits as its factorization.
3125132342531 is an evil number, because the sum of its binary digits is even.
The product of its digits is 64800, while the sum is 35.
Adding to 3125132342531 its reverse (1352432315213), we get a palindrome (4477564657744).
The spelling of 3125132342531 in words is "three trillion, one hundred twenty-five billion, one hundred thirty-two million, three hundred forty-two thousand, five hundred thirty-one".
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