Base | Representation |
---|---|
bin | 101101011110101010101… |
… | …000101101110101110001 |
3 | 102001202221210220020121221 |
4 | 231132222220231311301 |
5 | 402201110312240213 |
6 | 10351424515345041 |
7 | 441536642614423 |
oct | 55365250556561 |
9 | 12052853806557 |
10 | 3125304024433 |
11 | aa5485710968 |
12 | 425855bb2181 |
13 | 19893a852666 |
14 | ab3a0840813 |
15 | 5646a1a738d |
hex | 2d7aaa2dd71 |
3125304024433 has 8 divisors (see below), whose sum is σ = 3322718635968. Its totient is φ = 2933017065264.
The previous prime is 3125304024431. The next prime is 3125304024461. The reversal of 3125304024433 is 3344204035213.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 3125304024433 - 21 = 3125304024431 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3125304024431) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1281911835 + ... + 1281914272.
It is an arithmetic number, because the mean of its divisors is an integer number (415339829496).
Almost surely, 23125304024433 is an apocalyptic number.
It is an amenable number.
3125304024433 is a deficient number, since it is larger than the sum of its proper divisors (197414611535).
3125304024433 is a wasteful number, since it uses less digits than its factorization.
3125304024433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2563826183.
The product of its (nonzero) digits is 103680, while the sum is 34.
Adding to 3125304024433 its reverse (3344204035213), we get a palindrome (6469508059646).
The spelling of 3125304024433 in words is "three trillion, one hundred twenty-five billion, three hundred four million, twenty-four thousand, four hundred thirty-three".
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