31300113121 has 4 divisors (see below), whose sum is σ = 31301129412. Its totient is φ = 31299096832.

The previous prime is 31300113107. The next prime is 31300113127. The reversal of 31300113121 is 12131100313.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 18568150225 + 12731962896 = 136265^2 + 112836^2 .

It is a cyclic number.

It is not a de Polignac number, because 31300113121 - 2²⁵ = 31266558689 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 31300113095 and 31300113104.

It is not an unprimeable number, because it can be changed into a prime (31300113127) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 460456 + ... + 524041.

It is an arithmetic number, because the mean of its divisors is an integer number (7825282353).

Almost surely, 2^31300113121 is an apocalyptic number.

It is an amenable number.

31300113121 is a deficient number, since it is larger than the sum of its proper divisors (1016291).

31300113121 is an equidigital number, since it uses as much as digits as its factorization.

31300113121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1016290.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 31300113121 its reverse (12131100313), we get a palindrome (43431213434).

The spelling of 31300113121 in words is "thirty-one billion, three hundred million, one hundred thirteen thousand, one hundred twenty-one".