Base | Representation |
---|---|
bin | 100011100101011000111101… |
… | …0111111011110000110010010 |
3 | 1112001020201010112012100220222 |
4 | 1013022301322333132012102 |
5 | 312011211300112401002 |
6 | 3025411102453433042 |
7 | 122633440554134234 |
oct | 10712617277360622 |
9 | 1461221115170828 |
10 | 313002100122002 |
11 | 90806499630a35 |
12 | 2b131aa203b782 |
13 | 10585c821c1775 |
14 | 574154d73a254 |
15 | 262bd825841a2 |
hex | 11cac7afde192 |
313002100122002 has 4 divisors (see below), whose sum is σ = 469503150183006. Its totient is φ = 156501050061000.
The previous prime is 313002100122001. The next prime is 313002100122139. The reversal of 313002100122002 is 200221001200313.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 238778550956521 + 74223549165481 = 15452461^2 + 8615309^2 .
It is not an unprimeable number, because it can be changed into a prime (313002100122001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 78250525030499 + ... + 78250525030502.
Almost surely, 2313002100122002 is an apocalyptic number.
313002100122002 is a deficient number, since it is larger than the sum of its proper divisors (156501050061004).
313002100122002 is a wasteful number, since it uses less digits than its factorization.
313002100122002 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 156501050061003.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 313002100122002 its reverse (200221001200313), we get a palindrome (513223101322315).
The spelling of 313002100122002 in words is "three hundred thirteen trillion, two billion, one hundred million, one hundred twenty-two thousand, two".
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