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313002100122002 = 2156501050061001
BaseRepresentation
bin100011100101011000111101…
…0111111011110000110010010
31112001020201010112012100220222
41013022301322333132012102
5312011211300112401002
63025411102453433042
7122633440554134234
oct10712617277360622
91461221115170828
10313002100122002
1190806499630a35
122b131aa203b782
1310585c821c1775
14574154d73a254
15262bd825841a2
hex11cac7afde192

313002100122002 has 4 divisors (see below), whose sum is σ = 469503150183006. Its totient is φ = 156501050061000.

The previous prime is 313002100122001. The next prime is 313002100122139. The reversal of 313002100122002 is 200221001200313.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 238778550956521 + 74223549165481 = 15452461^2 + 8615309^2 .

It is not an unprimeable number, because it can be changed into a prime (313002100122001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 78250525030499 + ... + 78250525030502.

Almost surely, 2313002100122002 is an apocalyptic number.

313002100122002 is a deficient number, since it is larger than the sum of its proper divisors (156501050061004).

313002100122002 is a wasteful number, since it uses less digits than its factorization.

313002100122002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 156501050061003.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 313002100122002 its reverse (200221001200313), we get a palindrome (513223101322315).

The spelling of 313002100122002 in words is "three hundred thirteen trillion, two billion, one hundred million, one hundred twenty-two thousand, two".

Divisors: 1 2 156501050061001 313002100122002