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31301033000131 is a prime number
BaseRepresentation
bin1110001110111110101101…
…11100111111110011000011
311002211100102210211001111101
413013133112330333303003
513100314003422001011
6150323255051355231
76410265530414026
oct707372674776303
9132740383731441
1031301033000131
119a7876a126564
123616424752b17
1314608a055926b
147a2d99bd31bd
1539432974d2c1
hex1c77d6f3fcc3

31301033000131 has 2 divisors, whose sum is σ = 31301033000132. Its totient is φ = 31301033000130.

The previous prime is 31301033000099. The next prime is 31301033000137. The reversal of 31301033000131 is 13100033010313.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 31301033000131 - 25 = 31301033000099 is a prime.

It is a super-2 number, since 2×313010330001312 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 31301033000099 and 31301033000108.

It is not a weakly prime, because it can be changed into another prime (31301033000137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15650516500065 + 15650516500066.

It is an arithmetic number, because the mean of its divisors is an integer number (15650516500066).

Almost surely, 231301033000131 is an apocalyptic number.

31301033000131 is a deficient number, since it is larger than the sum of its proper divisors (1).

31301033000131 is an equidigital number, since it uses as much as digits as its factorization.

31301033000131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 243, while the sum is 19.

Adding to 31301033000131 its reverse (13100033010313), we get a palindrome (44401066010444).

The spelling of 31301033000131 in words is "thirty-one trillion, three hundred one billion, thirty-three million, one hundred thirty-one", and thus it is an aban number.