Base | Representation |
---|---|
bin | 1001000111000001110… |
… | …10111110010000000111 |
3 | 1002220221021210112010121 |
4 | 10203200322332100013 |
5 | 20112021331413111 |
6 | 355443444202411 |
7 | 31420465211134 |
oct | 4434072762007 |
9 | 1086837715117 |
10 | 313011201031 |
11 | 110824732201 |
12 | 507b6999407 |
13 | 23694622a29 |
14 | 1121518558b |
15 | 821eac4871 |
hex | 48e0ebe407 |
313011201031 has 2 divisors, whose sum is σ = 313011201032. Its totient is φ = 313011201030.
The previous prime is 313011200959. The next prime is 313011201037. The reversal of 313011201031 is 130102110313.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 313011201031 - 233 = 304421266439 is a prime.
It is a super-2 number, since 2×3130112010312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 313011200996 and 313011201014.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (313011201037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156505600515 + 156505600516.
It is an arithmetic number, because the mean of its divisors is an integer number (156505600516).
Almost surely, 2313011201031 is an apocalyptic number.
313011201031 is a deficient number, since it is larger than the sum of its proper divisors (1).
313011201031 is an equidigital number, since it uses as much as digits as its factorization.
313011201031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 313011201031 its reverse (130102110313), we get a palindrome (443113311344).
The spelling of 313011201031 in words is "three hundred thirteen billion, eleven million, two hundred one thousand, thirty-one".
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