Base | Representation |
---|---|
bin | 101101100011001110100… |
… | …001001100100111011011 |
3 | 102002020121002102101210121 |
4 | 231203032201030213123 |
5 | 402241122424003121 |
6 | 10353554450454111 |
7 | 442102204333342 |
oct | 55431641144733 |
9 | 12066532371717 |
10 | 3130201000411 |
11 | aa7568951451 |
12 | 4267a1b94337 |
13 | 19923b24c194 |
14 | ab706d64b59 |
15 | 5665505d141 |
hex | 2d8ce84c9db |
3130201000411 has 2 divisors, whose sum is σ = 3130201000412. Its totient is φ = 3130201000410.
The previous prime is 3130201000393. The next prime is 3130201000441. The reversal of 3130201000411 is 1140001020313.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3130201000411 - 215 = 3130200967643 is a prime.
It is not a weakly prime, because it can be changed into another prime (3130201000441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1565100500205 + 1565100500206.
It is an arithmetic number, because the mean of its divisors is an integer number (1565100500206).
Almost surely, 23130201000411 is an apocalyptic number.
3130201000411 is a deficient number, since it is larger than the sum of its proper divisors (1).
3130201000411 is an equidigital number, since it uses as much as digits as its factorization.
3130201000411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 3130201000411 its reverse (1140001020313), we get a palindrome (4270202020724).
The spelling of 3130201000411 in words is "three trillion, one hundred thirty billion, two hundred one million, four hundred eleven", and thus it is an aban number.
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