Base | Representation |
---|---|
bin | 100011100101100111100000… |
… | …1000010001011110111111101 |
3 | 1112001100200202200120002212002 |
4 | 1013023033001002023313331 |
5 | 312012214240020304411 |
6 | 3025433310420552045 |
7 | 122635624660611653 |
oct | 10713170102136775 |
9 | 1461320680502762 |
10 | 313033340009981 |
11 | 9081876a745178 |
12 | 2b137b60252625 |
13 | 10588bc0405896 |
14 | 5742c746d8dd3 |
15 | 262caaee7733b |
hex | 11cb3c108bdfd |
313033340009981 has 2 divisors, whose sum is σ = 313033340009982. Its totient is φ = 313033340009980.
The previous prime is 313033340009977. The next prime is 313033340010019. The reversal of 313033340009981 is 189900043330313.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 281530478476900 + 31502861533081 = 16778870^2 + 5612741^2 .
It is a cyclic number.
It is not a de Polignac number, because 313033340009981 - 22 = 313033340009977 is a prime.
It is a super-2 number, since 2×3130333400099812 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (313033340009921) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156516670004990 + 156516670004991.
It is an arithmetic number, because the mean of its divisors is an integer number (156516670004991).
Almost surely, 2313033340009981 is an apocalyptic number.
It is an amenable number.
313033340009981 is a deficient number, since it is larger than the sum of its proper divisors (1).
313033340009981 is an equidigital number, since it uses as much as digits as its factorization.
313033340009981 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 629856, while the sum is 47.
The spelling of 313033340009981 in words is "three hundred thirteen trillion, thirty-three billion, three hundred forty million, nine thousand, nine hundred eighty-one".
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