Base | Representation |
---|---|
bin | 100011100101110000011011… |
… | …1010101000111101001110111 |
3 | 1112001102112020022000211002112 |
4 | 1013023200313111013221313 |
5 | 312013023012131212403 |
6 | 3025450200223401235 |
7 | 122640203616551306 |
oct | 10713406725075167 |
9 | 1461375208024075 |
10 | 313052504554103 |
11 | 90825904616896 |
12 | 2b13b80a45321b |
13 | 1058a955995212 |
14 | 5743b71a6643d |
15 | 262d3326b59d8 |
hex | 11cb837547a77 |
313052504554103 has 4 divisors (see below), whose sum is σ = 313706058843840. Its totient is φ = 312398950264368.
The previous prime is 313052504554099. The next prime is 313052504554117. The reversal of 313052504554103 is 301455405250313.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 313052504554103 - 22 = 313052504554099 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (313052504554183) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 326777144150 + ... + 326777145107.
It is an arithmetic number, because the mean of its divisors is an integer number (78426514710960).
Almost surely, 2313052504554103 is an apocalyptic number.
313052504554103 is a deficient number, since it is larger than the sum of its proper divisors (653554289737).
313052504554103 is an equidigital number, since it uses as much as digits as its factorization.
313052504554103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 653554289736.
The product of its (nonzero) digits is 540000, while the sum is 41.
The spelling of 313052504554103 in words is "three hundred thirteen trillion, fifty-two billion, five hundred four million, five hundred fifty-four thousand, one hundred three".
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