Base | Representation |
---|---|
bin | 101101100011100010110… |
… | …010011000100100100001 |
3 | 102002021110210021201100012 |
4 | 231203202302120210201 |
5 | 402242322002101040 |
6 | 10354052315134305 |
7 | 442113503606105 |
oct | 55434262304441 |
9 | 12067423251305 |
10 | 3130541050145 |
11 | aa772289a893 |
12 | 426877a44395 |
13 | 199293830342 |
14 | ab73a1a1905 |
15 | 56674d2d865 |
hex | 2d8e2c98921 |
3130541050145 has 4 divisors (see below), whose sum is σ = 3756649260180. Its totient is φ = 2504432840112.
The previous prime is 3130541050123. The next prime is 3130541050159. The reversal of 3130541050145 is 5410501450313.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1115708425441 + 2014832624704 = 1056271^2 + 1419448^2 .
It is a cyclic number.
It is not a de Polignac number, because 3130541050145 - 222 = 3130536855841 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 313054105010 + ... + 313054105019.
It is an arithmetic number, because the mean of its divisors is an integer number (939162315045).
Almost surely, 23130541050145 is an apocalyptic number.
It is an amenable number.
3130541050145 is a deficient number, since it is larger than the sum of its proper divisors (626108210035).
3130541050145 is an equidigital number, since it uses as much as digits as its factorization.
3130541050145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 626108210034.
The product of its (nonzero) digits is 18000, while the sum is 32.
The spelling of 3130541050145 in words is "three trillion, one hundred thirty billion, five hundred forty-one million, fifty thousand, one hundred forty-five".
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