Base | Representation |
---|---|
bin | 100011100110000110100110… |
… | …1000001011000111011110011 |
3 | 1112001121002010012221121020101 |
4 | 1013030031031001120323303 |
5 | 312014313012424333021 |
6 | 3025524112320253231 |
7 | 122643510452651026 |
oct | 10714151501307363 |
9 | 1461532105847211 |
10 | 313100113121011 |
11 | 90844015398857 |
12 | 2b148a96471217 |
13 | 105922a2158778 |
14 | 57461aa9271bd |
15 | 262e6bc127a91 |
hex | 11cc34d058ef3 |
313100113121011 has 2 divisors, whose sum is σ = 313100113121012. Its totient is φ = 313100113121010.
The previous prime is 313100113121009. The next prime is 313100113121083. The reversal of 313100113121011 is 110121311001313.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 313100113121011 - 21 = 313100113121009 is a prime.
Together with 313100113121009, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 313100113121011.
It is not a weakly prime, because it can be changed into another prime (313100113124011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156550056560505 + 156550056560506.
It is an arithmetic number, because the mean of its divisors is an integer number (156550056560506).
Almost surely, 2313100113121011 is an apocalyptic number.
313100113121011 is a deficient number, since it is larger than the sum of its proper divisors (1).
313100113121011 is an equidigital number, since it uses as much as digits as its factorization.
313100113121011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 19.
Adding to 313100113121011 its reverse (110121311001313), we get a palindrome (423221424122324).
The spelling of 313100113121011 in words is "three hundred thirteen trillion, one hundred billion, one hundred thirteen million, one hundred twenty-one thousand, eleven".
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