Base | Representation |
---|---|
bin | 100011100110001000001001… |
… | …0001100110011000110000111 |
3 | 1112001121101122202201121110111 |
4 | 1013030100102030303012013 |
5 | 312014341301313121203 |
6 | 3025525420452333451 |
7 | 122643655442240104 |
oct | 10714202214630607 |
9 | 1461541582647414 |
10 | 313103421223303 |
11 | 90845462766a97 |
12 | 2b14965a314287 |
13 | 105926ab616949 |
14 | 5746402011aab |
15 | 262e81277b26d |
hex | 11cc412333187 |
313103421223303 has 2 divisors, whose sum is σ = 313103421223304. Its totient is φ = 313103421223302.
The previous prime is 313103421223273. The next prime is 313103421223339. The reversal of 313103421223303 is 303322124301313.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 313103421223303 - 213 = 313103421215111 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (313103421223393) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156551710611651 + 156551710611652.
It is an arithmetic number, because the mean of its divisors is an integer number (156551710611652).
Almost surely, 2313103421223303 is an apocalyptic number.
313103421223303 is a deficient number, since it is larger than the sum of its proper divisors (1).
313103421223303 is an equidigital number, since it uses as much as digits as its factorization.
313103421223303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 23328, while the sum is 31.
Adding to 313103421223303 its reverse (303322124301313), we get a palindrome (616425545524616).
The spelling of 313103421223303 in words is "three hundred thirteen trillion, one hundred three billion, four hundred twenty-one million, two hundred twenty-three thousand, three hundred three".
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