Base | Representation |
---|---|
bin | 100011100110001000001001… |
… | …0111010111000011111100101 |
3 | 1112001121101200121110101010002 |
4 | 1013030100102322320133211 |
5 | 312014341312411212122 |
6 | 3025525422003311045 |
7 | 122643655650023645 |
oct | 10714202272703745 |
9 | 1461541617411102 |
10 | 313103433304037 |
11 | 90845469568472 |
12 | 2b14966237b485 |
13 | 105926b0c865cc |
14 | 5746403878525 |
15 | 262e813865992 |
hex | 11cc412eb87e5 |
313103433304037 has 2 divisors, whose sum is σ = 313103433304038. Its totient is φ = 313103433304036.
The previous prime is 313103433304021. The next prime is 313103433304133. The reversal of 313103433304037 is 730403334301313.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 302743783417156 + 10359649886881 = 17399534^2 + 3218641^2 .
It is an emirp because it is prime and its reverse (730403334301313) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 313103433304037 - 24 = 313103433304021 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (313103433354037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156551716652018 + 156551716652019.
It is an arithmetic number, because the mean of its divisors is an integer number (156551716652019).
Almost surely, 2313103433304037 is an apocalyptic number.
It is an amenable number.
313103433304037 is a deficient number, since it is larger than the sum of its proper divisors (1).
313103433304037 is an equidigital number, since it uses as much as digits as its factorization.
313103433304037 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 244944, while the sum is 38.
The spelling of 313103433304037 in words is "three hundred thirteen trillion, one hundred three billion, four hundred thirty-three million, three hundred four thousand, thirty-seven".
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