Base | Representation |
---|---|
bin | 1110001111010001100000… |
… | …10011100001110001011101 |
3 | 11002212022110221002000200221 |
4 | 13013220300103201301131 |
5 | 13101000134213411102 |
6 | 150332044134121341 |
7 | 6411103535541361 |
oct | 707506023416135 |
9 | 132768427060627 |
10 | 31311122013277 |
11 | 9a81a77108457 |
12 | 361837b4b0251 |
13 | 146181a811422 |
14 | 7a3675ac72a1 |
15 | 39471a340637 |
hex | 1c7a304e1c5d |
31311122013277 has 2 divisors, whose sum is σ = 31311122013278. Its totient is φ = 31311122013276.
The previous prime is 31311122013239. The next prime is 31311122013329. The reversal of 31311122013277 is 77231022111313.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 30345764672601 + 965357340676 = 5508699^2 + 982526^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31311122013277 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31311122023277) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15655561006638 + 15655561006639.
It is an arithmetic number, because the mean of its divisors is an integer number (15655561006639).
Almost surely, 231311122013277 is an apocalyptic number.
It is an amenable number.
31311122013277 is a deficient number, since it is larger than the sum of its proper divisors (1).
31311122013277 is an equidigital number, since it uses as much as digits as its factorization.
31311122013277 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10584, while the sum is 34.
The spelling of 31311122013277 in words is "thirty-one trillion, three hundred eleven billion, one hundred twenty-two million, thirteen thousand, two hundred seventy-seven".
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