Base | Representation |
---|---|
bin | 1110001111010001100000… |
… | …10011100001110010001011 |
3 | 11002212022110221002000202122 |
4 | 13013220300103201302023 |
5 | 13101000134213411243 |
6 | 150332044134121455 |
7 | 6411103535541455 |
oct | 707506023416213 |
9 | 132768427060678 |
10 | 31311122013323 |
11 | 9a81a77108499 |
12 | 361837b4b028b |
13 | 146181a811459 |
14 | 7a3675ac72d5 |
15 | 39471a340668 |
hex | 1c7a304e1c8b |
31311122013323 has 4 divisors (see below), whose sum is σ = 31484111637888. Its totient is φ = 31138132388760.
The previous prime is 31311122013277. The next prime is 31311122013329. The reversal of 31311122013323 is 32331022111313.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 31311122013323 - 218 = 31311121751179 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 31311122013292 and 31311122013301.
It is not an unprimeable number, because it can be changed into a prime (31311122013329) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 86494812011 + ... + 86494812372.
It is an arithmetic number, because the mean of its divisors is an integer number (7871027909472).
Almost surely, 231311122013323 is an apocalyptic number.
31311122013323 is a deficient number, since it is larger than the sum of its proper divisors (172989624565).
31311122013323 is a wasteful number, since it uses less digits than its factorization.
31311122013323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 172989624564.
The product of its (nonzero) digits is 1944, while the sum is 26.
Adding to 31311122013323 its reverse (32331022111313), we get a palindrome (63642144124636).
The spelling of 31311122013323 in words is "thirty-one trillion, three hundred eleven billion, one hundred twenty-two million, thirteen thousand, three hundred twenty-three".
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