Base | Representation |
---|---|
bin | 11101001010010011… |
… | …001011010011100111 |
3 | 2222211010202110102001 |
4 | 131022103023103213 |
5 | 1003111143441403 |
6 | 22214554030131 |
7 | 2155631522131 |
oct | 351223132347 |
9 | 88733673361 |
10 | 31311312103 |
11 | 12308468245 |
12 | 609a118347 |
13 | 2c4cc60c16 |
14 | 1730672051 |
15 | c33d00c1d |
hex | 74a4cb4e7 |
31311312103 has 2 divisors, whose sum is σ = 31311312104. Its totient is φ = 31311312102.
The previous prime is 31311312073. The next prime is 31311312119. The reversal of 31311312103 is 30121311313.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 31311312103 - 213 = 31311303911 is a prime.
It is a super-2 number, since 2×313113121032 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31311312503) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15655656051 + 15655656052.
It is an arithmetic number, because the mean of its divisors is an integer number (15655656052).
Almost surely, 231311312103 is an apocalyptic number.
31311312103 is a deficient number, since it is larger than the sum of its proper divisors (1).
31311312103 is an equidigital number, since it uses as much as digits as its factorization.
31311312103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 31311312103 its reverse (30121311313), we get a palindrome (61432623416).
The spelling of 31311312103 in words is "thirty-one billion, three hundred eleven million, three hundred twelve thousand, one hundred three".
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