Base | Representation |
---|---|
bin | 1110001111010001110111… |
… | …01001000100110101100111 |
3 | 11002212022222011222002100021 |
4 | 13013220323221010311213 |
5 | 13101001031411230203 |
6 | 150332115050500011 |
7 | 6411111335312515 |
oct | 707507351046547 |
9 | 132768864862307 |
10 | 31311312211303 |
11 | 9a82064506003 |
12 | 3618413134607 |
13 | 146184b046037 |
14 | 7a36930774b5 |
15 | 39472bdb05bd |
hex | 1c7a3ba44d67 |
31311312211303 has 4 divisors (see below), whose sum is σ = 31311491460408. Its totient is φ = 31311132962200.
The previous prime is 31311312211301. The next prime is 31311312211327. The reversal of 31311312211303 is 30311221311313.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 31311312211303 - 21 = 31311312211301 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31311312211301) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 89362276 + ... + 89711977.
It is an arithmetic number, because the mean of its divisors is an integer number (7827872865102).
Almost surely, 231311312211303 is an apocalyptic number.
31311312211303 is a deficient number, since it is larger than the sum of its proper divisors (179249105).
31311312211303 is a wasteful number, since it uses less digits than its factorization.
31311312211303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 179249104.
The product of its (nonzero) digits is 972, while the sum is 25.
Adding to 31311312211303 its reverse (30311221311313), we get a palindrome (61622533522616).
The spelling of 31311312211303 in words is "thirty-one trillion, three hundred eleven billion, three hundred twelve million, two hundred eleven thousand, three hundred three".
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