Base | Representation |
---|---|
bin | 1001000111001110111… |
… | …01111001110110011101 |
3 | 1002221012221102222021111 |
4 | 10203213131321312131 |
5 | 20112232440140331 |
6 | 355502410102021 |
7 | 31423300524022 |
oct | 4434735716635 |
9 | 1087187388244 |
10 | 313121021341 |
11 | 110880720897 |
12 | 5082771a911 |
13 | 236b12c436b |
14 | 112259b1549 |
15 | 8229568db1 |
hex | 48e7779d9d |
313121021341 has 2 divisors, whose sum is σ = 313121021342. Its totient is φ = 313121021340.
The previous prime is 313121021309. The next prime is 313121021357. The reversal of 313121021341 is 143120121313.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 174372221241 + 138748800100 = 417579^2 + 372490^2 .
It is a cyclic number.
It is not a de Polignac number, because 313121021341 - 25 = 313121021309 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (313121021641) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156560510670 + 156560510671.
It is an arithmetic number, because the mean of its divisors is an integer number (156560510671).
Almost surely, 2313121021341 is an apocalyptic number.
It is an amenable number.
313121021341 is a deficient number, since it is larger than the sum of its proper divisors (1).
313121021341 is an equidigital number, since it uses as much as digits as its factorization.
313121021341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 313121021341 its reverse (143120121313), we get a palindrome (456241142654).
The spelling of 313121021341 in words is "three hundred thirteen billion, one hundred twenty-one million, twenty-one thousand, three hundred forty-one".
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