Base | Representation |
---|---|
bin | 1110001111010011010110… |
… | …01100011110101000001011 |
3 | 11002212102000210012000200102 |
4 | 13013221223030132220023 |
5 | 13101004200131134011 |
6 | 150332330150400015 |
7 | 6411140163504632 |
oct | 707515314365013 |
9 | 132772023160612 |
10 | 31312110021131 |
11 | 9a82433890375 |
12 | 36185b636000b |
13 | 1461947410064 |
14 | 7a372add2519 |
15 | 394776e5373b |
hex | 1c7a6b31ea0b |
31312110021131 has 2 divisors, whose sum is σ = 31312110021132. Its totient is φ = 31312110021130.
The previous prime is 31312110021121. The next prime is 31312110021133. The reversal of 31312110021131 is 13112001121313.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 31312110021131 - 218 = 31312109758987 is a prime.
It is a super-2 number, since 2×313121100211312 (a number of 28 digits) contains 22 as substring.
Together with 31312110021133, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (31312110021133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15656055010565 + 15656055010566.
It is an arithmetic number, because the mean of its divisors is an integer number (15656055010566).
Almost surely, 231312110021131 is an apocalyptic number.
31312110021131 is a deficient number, since it is larger than the sum of its proper divisors (1).
31312110021131 is an equidigital number, since it uses as much as digits as its factorization.
31312110021131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 20.
Adding to 31312110021131 its reverse (13112001121313), we get a palindrome (44424111142444).
The spelling of 31312110021131 in words is "thirty-one trillion, three hundred twelve billion, one hundred ten million, twenty-one thousand, one hundred thirty-one".
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