Base | Representation |
---|---|
bin | 101101100100001010110… |
… | …001111011100111000001 |
3 | 102002100012112211112011112 |
4 | 231210022301323213001 |
5 | 402300210234121121 |
6 | 10354243044253105 |
7 | 442136232011651 |
oct | 55441261734701 |
9 | 12070175745145 |
10 | 3131212020161 |
11 | aa7a37611565 |
12 | 426a246a1195 |
13 | 19936c847114 |
14 | ab7a1340361 |
15 | 566b3bb975b |
hex | 2d90ac7b9c1 |
3131212020161 has 2 divisors, whose sum is σ = 3131212020162. Its totient is φ = 3131212020160.
The previous prime is 3131212020071. The next prime is 3131212020169. The reversal of 3131212020161 is 1610202121313.
3131212020161 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3017933328400 + 113278691761 = 1737220^2 + 336569^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3131212020161 is a prime.
It is not a weakly prime, because it can be changed into another prime (3131212020169) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1565606010080 + 1565606010081.
It is an arithmetic number, because the mean of its divisors is an integer number (1565606010081).
Almost surely, 23131212020161 is an apocalyptic number.
It is an amenable number.
3131212020161 is a deficient number, since it is larger than the sum of its proper divisors (1).
3131212020161 is an equidigital number, since it uses as much as digits as its factorization.
3131212020161 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 3131212020161 its reverse (1610202121313), we get a palindrome (4741414141474).
The spelling of 3131212020161 in words is "three trillion, one hundred thirty-one billion, two hundred twelve million, twenty thousand, one hundred sixty-one".
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