Base | Representation |
---|---|
bin | 100011100110010001110001… |
… | …0111111101101100010011111 |
3 | 1112001200101001012012121102201 |
4 | 1013030203202333231202133 |
5 | 312020211131122144444 |
6 | 3025543121054232331 |
7 | 122645320125630133 |
oct | 10714434277554237 |
9 | 1461611035177381 |
10 | 313124104099999 |
11 | 908532066aa415 |
12 | 2b151670ab56a7 |
13 | 10594626616a1a |
14 | 5747404c953c3 |
15 | 2630123435dd4 |
hex | 11cc8e2fed89f |
313124104099999 has 2 divisors, whose sum is σ = 313124104100000. Its totient is φ = 313124104099998.
The previous prime is 313124104099949. The next prime is 313124104100021. The reversal of 313124104099999 is 999990401421313.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 313124104099999 - 223 = 313124095711391 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 313124104099999.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (313124104099949) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156562052049999 + 156562052050000.
It is an arithmetic number, because the mean of its divisors is an integer number (156562052050000).
Almost surely, 2313124104099999 is an apocalyptic number.
313124104099999 is a deficient number, since it is larger than the sum of its proper divisors (1).
313124104099999 is an equidigital number, since it uses as much as digits as its factorization.
313124104099999 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17006112, while the sum is 64.
The spelling of 313124104099999 in words is "three hundred thirteen trillion, one hundred twenty-four billion, one hundred four million, ninety-nine thousand, nine hundred ninety-nine".
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