Base | Representation |
---|---|
bin | 1110001111010101000000… |
… | …01111100101111101011001 |
3 | 11002212111022210220011101101 |
4 | 13013222200033211331121 |
5 | 13101013011001430131 |
6 | 150332554342351401 |
7 | 6411201221452042 |
oct | 707524017457531 |
9 | 132774283804341 |
10 | 31313000030041 |
11 | 9a82850209224 |
12 | 361880442b561 |
13 | 1461a59918c52 |
14 | 7a37b32ab8c9 |
15 | 3947ca159c61 |
hex | 1c7aa03e5f59 |
31313000030041 has 2 divisors, whose sum is σ = 31313000030042. Its totient is φ = 31313000030040.
The previous prime is 31313000029981. The next prime is 31313000030093. The reversal of 31313000030041 is 14003000031313.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 17136991899225 + 14176008130816 = 4139685^2 + 3765104^2 .
It is a cyclic number.
It is not a de Polignac number, because 31313000030041 - 215 = 31312999997273 is a prime.
It is not a weakly prime, because it can be changed into another prime (31313001030041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15656500015020 + 15656500015021.
It is an arithmetic number, because the mean of its divisors is an integer number (15656500015021).
Almost surely, 231313000030041 is an apocalyptic number.
It is an amenable number.
31313000030041 is a deficient number, since it is larger than the sum of its proper divisors (1).
31313000030041 is an equidigital number, since it uses as much as digits as its factorization.
31313000030041 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 31313000030041 its reverse (14003000031313), we get a palindrome (45316000061354).
The spelling of 31313000030041 in words is "thirty-one trillion, three hundred thirteen billion, thirty thousand, forty-one".
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