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31313340151 = 56599553249
BaseRepresentation
bin11101001010011010…
…111010011011110111
32222211021120111100221
4131022122322123313
51003112203341101
622215105315211
72155654666612
oct351232723367
988737514327
1031313340151
1112309622a15
12609a935b07
132c504c1052
141730a3d179
15c340a1aa1
hex74a6ba6f7

31313340151 has 4 divisors (see below), whose sum is σ = 31313950000. Its totient is φ = 31312730304.

The previous prime is 31313340137. The next prime is 31313340169. The reversal of 31313340151 is 15104331313.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 15104331313 = 25935825041.

It is a cyclic number.

It is not a de Polignac number, because 31313340151 - 29 = 31313339639 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31313340101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 220026 + ... + 333223.

It is an arithmetic number, because the mean of its divisors is an integer number (7828487500).

Almost surely, 231313340151 is an apocalyptic number.

31313340151 is a deficient number, since it is larger than the sum of its proper divisors (609849).

31313340151 is an equidigital number, since it uses as much as digits as its factorization.

31313340151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 609848.

The product of its (nonzero) digits is 1620, while the sum is 25.

Adding to 31313340151 its reverse (15104331313), we get a palindrome (46417671464).

The spelling of 31313340151 in words is "thirty-one billion, three hundred thirteen million, three hundred forty thousand, one hundred fifty-one".

Divisors: 1 56599 553249 31313340151