313144550403 has 4 divisors (see below), whose sum is σ = 417526067208. Its totient is φ = 208763033600.

The previous prime is 313144550377. The next prime is 313144550417. The reversal of 313144550403 is 304055441313.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 313144550403 - 2³³ = 304554615811 is a prime.

It is not an unprimeable number, because it can be changed into a prime (313144550443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52190758398 + ... + 52190758403.

It is an arithmetic number, because the mean of its divisors is an integer number (104381516802).

Almost surely, 2^313144550403 is an apocalyptic number.

313144550403 is a deficient number, since it is larger than the sum of its proper divisors (104381516805).

313144550403 is a wasteful number, since it uses less digits than its factorization.

313144550403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 104381516804.

The product of its (nonzero) digits is 43200, while the sum is 33.

Adding to 313144550403 its reverse (304055441313), we get a palindrome (617199991716).

The spelling of 313144550403 in words is "three hundred thirteen billion, one hundred forty-four million, five hundred fifty thousand, four hundred three".