Base | Representation |
---|---|
bin | 1110001111100010010000… |
… | …01101110100000101100010 |
3 | 11002220011200112101201101111 |
4 | 13013301020031310011202 |
5 | 13101122042423300302 |
6 | 150340132240253534 |
7 | 6411542412542500 |
oct | 707611015640542 |
9 | 132804615351344 |
10 | 31320113103202 |
11 | 9a85870373390 |
12 | 361a06a6112aa |
13 | 1462621491c91 |
14 | 7a3c89c5d670 |
15 | 394a9485c0d7 |
hex | 1c7c48374162 |
31320113103202 has 96 divisors (see below), whose sum is σ = 63154204053120. Its totient is φ = 11479634449920.
The previous prime is 31320113103179. The next prime is 31320113103217. The reversal of 31320113103202 is 20230131102313.
It is a super-2 number, since 2×313201131032022 (a number of 28 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (22).
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 40169299 + ... + 40941577.
It is an arithmetic number, because the mean of its divisors is an integer number (657856292220).
Almost surely, 231320113103202 is an apocalyptic number.
31320113103202 is an abundant number, since it is smaller than the sum of its proper divisors (31834090949918).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
31320113103202 is a wasteful number, since it uses less digits than its factorization.
31320113103202 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 774536 (or 774529 counting only the distinct ones).
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 31320113103202 its reverse (20230131102313), we get a palindrome (51550244205515).
The spelling of 31320113103202 in words is "thirty-one trillion, three hundred twenty billion, one hundred thirteen million, one hundred three thousand, two hundred two".
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