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313203123011993 is a prime number
BaseRepresentation
bin100011100110110110100100…
…0111000111100000110011001
31112001221221000011020020200212
41013031231020320330012121
5312023004443442340433
63030043310043540505
7122654115235405634
oct10715551070740631
91461857004206625
10313203123011993
119088377582a565
122b164a4422a735
131059bc0a403796
14574b17d606c1b
1526321ea70bd48
hex11cdb48e3c199

313203123011993 has 2 divisors, whose sum is σ = 313203123011994. Its totient is φ = 313203123011992.

The previous prime is 313203123011917. The next prime is 313203123012037. The reversal of 313203123011993 is 399110321302313.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 283236344959129 + 29966778052864 = 16829627^2 + 5474192^2 .

It is a cyclic number.

It is not a de Polignac number, because 313203123011993 - 212 = 313203123007897 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 313203123011993.

It is not a weakly prime, because it can be changed into another prime (313203123011903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156601561505996 + 156601561505997.

It is an arithmetic number, because the mean of its divisors is an integer number (156601561505997).

Almost surely, 2313203123011993 is an apocalyptic number.

It is an amenable number.

313203123011993 is a deficient number, since it is larger than the sum of its proper divisors (1).

313203123011993 is an equidigital number, since it uses as much as digits as its factorization.

313203123011993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 78732, while the sum is 41.

The spelling of 313203123011993 in words is "three hundred thirteen trillion, two hundred three billion, one hundred twenty-three million, eleven thousand, nine hundred ninety-three".