Base | Representation |
---|---|
bin | 1110001111101000001110… |
… | …11000010011100110101101 |
3 | 11002220110222001022022001001 |
4 | 13013310013120103212231 |
5 | 13101200124444130442 |
6 | 150341422405520301 |
7 | 6412015035354343 |
oct | 707640730234655 |
9 | 132813861268031 |
10 | 31323320301997 |
11 | 9a871667932a9 |
12 | 361a804713091 |
13 | 1462a12a81349 |
14 | 7a40b1b9d993 |
15 | 394bd11cd2b7 |
hex | 1c7d076139ad |
31323320301997 has 2 divisors, whose sum is σ = 31323320301998. Its totient is φ = 31323320301996.
The previous prime is 31323320301953. The next prime is 31323320302159. The reversal of 31323320301997 is 79910302332313.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 18440059167721 + 12883261134276 = 4294189^2 + 3589326^2 .
It is a cyclic number.
It is not a de Polignac number, because 31323320301997 - 215 = 31323320269229 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31323320307997) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15661660150998 + 15661660150999.
It is an arithmetic number, because the mean of its divisors is an integer number (15661660150999).
Almost surely, 231323320301997 is an apocalyptic number.
It is an amenable number.
31323320301997 is a deficient number, since it is larger than the sum of its proper divisors (1).
31323320301997 is an equidigital number, since it uses as much as digits as its factorization.
31323320301997 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 551124, while the sum is 46.
The spelling of 31323320301997 in words is "thirty-one trillion, three hundred twenty-three billion, three hundred twenty million, three hundred one thousand, nine hundred ninety-seven".
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