Base | Representation |
---|---|
bin | 1110001111101010000111… |
… | …01000101010100001100100 |
3 | 11002220120120111112102010212 |
4 | 13013311003220222201210 |
5 | 13101204212243120030 |
6 | 150342111001234552 |
7 | 6412052062142324 |
oct | 707650350524144 |
9 | 132816514472125 |
10 | 31324331223140 |
11 | 9a8763539631a |
12 | 361aa47192a58 |
13 | 1462b44343437 |
14 | 7a416a151284 |
15 | 394c3ed1a595 |
hex | 1c7d43a2a864 |
31324331223140 has 24 divisors (see below), whose sum is σ = 66216731969472. Its totient is φ = 12446754127200.
The previous prime is 31324331223023. The next prime is 31324331223169. The reversal of 31324331223140 is 4132213342313.
It is a junction number, because it is equal to n+sod(n) for n = 31324331223097 and 31324331223106.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5186144534 + ... + 5186150573.
It is an arithmetic number, because the mean of its divisors is an integer number (2759030498728).
Almost surely, 231324331223140 is an apocalyptic number.
It is an amenable number.
31324331223140 is an abundant number, since it is smaller than the sum of its proper divisors (34892400746332).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
31324331223140 is a wasteful number, since it uses less digits than its factorization.
31324331223140 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10372295267 (or 10372295265 counting only the distinct ones).
The product of its (nonzero) digits is 31104, while the sum is 32.
Adding to 31324331223140 its reverse (4132213342313), we get a palindrome (35456544565453).
The spelling of 31324331223140 in words is "thirty-one trillion, three hundred twenty-four billion, three hundred thirty-one million, two hundred twenty-three thousand, one hundred forty".
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