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313294249481 is a prime number
BaseRepresentation
bin1001000111100011100…
…10101101111000001001
31002221200000101212121112
410203301302231320021
520113111311440411
6355531515020105
731430503116233
oct4436162557011
91087600355545
10313294249481
1111095a488744
125087573a635
132370b166b15
14112409c5253
158239885b8b
hex48f1cade09

313294249481 has 2 divisors, whose sum is σ = 313294249482. Its totient is φ = 313294249480.

The previous prime is 313294249423. The next prime is 313294249493. The reversal of 313294249481 is 184942492313.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 157695557881 + 155598691600 = 397109^2 + 394460^2 .

It is a cyclic number.

It is not a de Polignac number, because 313294249481 - 226 = 313227140617 is a prime.

It is a super-3 number, since 3×3132942494813 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (313294240481) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156647124740 + 156647124741.

It is an arithmetic number, because the mean of its divisors is an integer number (156647124741).

Almost surely, 2313294249481 is an apocalyptic number.

It is an amenable number.

313294249481 is a deficient number, since it is larger than the sum of its proper divisors (1).

313294249481 is an equidigital number, since it uses as much as digits as its factorization.

313294249481 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1492992, while the sum is 50.

The spelling of 313294249481 in words is "three hundred thirteen billion, two hundred ninety-four million, two hundred forty-nine thousand, four hundred eighty-one".