31330113112019 has 2 divisors, whose sum is σ = 31330113112020. Its totient is φ = 31330113112018.

The previous prime is 31330113112009. The next prime is 31330113112021. The reversal of 31330113112019 is 91021131103313.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-31330113112019 is a prime.

It is a super-2 number, since 2×31330113112019² (a number of 28 digits) contains 22 as substring.

Together with 31330113112021, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 31330113111982 and 31330113112000.

It is not a weakly prime, because it can be changed into another prime (31330113112009) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15665056556009 + 15665056556010.

It is an arithmetic number, because the mean of its divisors is an integer number (15665056556010).

Almost surely, 2^{31330113112019} is an apocalyptic number.

31330113112019 is a deficient number, since it is larger than the sum of its proper divisors (1).

31330113112019 is an equidigital number, since it uses as much as digits as its factorization.

31330113112019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1458, while the sum is 29.

The spelling of 31330113112019 in words is "thirty-one trillion, three hundred thirty billion, one hundred thirteen million, one hundred twelve thousand, nineteen".