Base | Representation |
---|---|
bin | 1110001111110111001010… |
… | …11101011000000110101101 |
3 | 11002221020200000221002211221 |
4 | 13013323211131120012231 |
5 | 13101313041312443042 |
6 | 150345230332143341 |
7 | 6412420561355014 |
oct | 707734535300655 |
9 | 132836600832757 |
10 | 31331341140397 |
11 | 9a8a6022a3971 |
12 | 3620282907b51 |
13 | 14636c070c37c |
14 | 7a463312da7b |
15 | 395000442d67 |
hex | 1c7ee57581ad |
31331341140397 has 2 divisors, whose sum is σ = 31331341140398. Its totient is φ = 31331341140396.
The previous prime is 31331341140389. The next prime is 31331341140427. The reversal of 31331341140397 is 79304114313313.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 26657663567236 + 4673677573161 = 5163106^2 + 2161869^2 .
It is a cyclic number.
It is not a de Polignac number, because 31331341140397 - 23 = 31331341140389 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31331341140317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15665670570198 + 15665670570199.
It is an arithmetic number, because the mean of its divisors is an integer number (15665670570199).
Almost surely, 231331341140397 is an apocalyptic number.
It is an amenable number.
31331341140397 is a deficient number, since it is larger than the sum of its proper divisors (1).
31331341140397 is an equidigital number, since it uses as much as digits as its factorization.
31331341140397 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 244944, while the sum is 43.
The spelling of 31331341140397 in words is "thirty-one trillion, three hundred thirty-one billion, three hundred forty-one million, one hundred forty thousand, three hundred ninety-seven".
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