313331124120133 has 8 divisors (see below), whose sum is σ = 358947349830720. Its totient is φ = 267928557547200.

The previous prime is 313331124120101. The next prime is 313331124120163. The reversal of 313331124120133 is 331021421133313.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 313331124120133 - 2⁵ = 313331124120101 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 313331124120095 and 313331124120104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (313331124120163) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 53414781268 + ... + 53414787133.

It is an arithmetic number, because the mean of its divisors is an integer number (44868418728840).

Almost surely, 2^{313331124120133} is an apocalyptic number.

It is an amenable number.

313331124120133 is a deficient number, since it is larger than the sum of its proper divisors (45616225710587).

313331124120133 is a wasteful number, since it uses less digits than its factorization.

313331124120133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 106829568827.

The product of its (nonzero) digits is 11664, while the sum is 31.

Adding to 313331124120133 its reverse (331021421133313), we get a palindrome (644352545253446).

The spelling of 313331124120133 in words is "three hundred thirteen trillion, three hundred thirty-one billion, one hundred twenty-four million, one hundred twenty thousand, one hundred thirty-three".