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313404181231 is a prime number
BaseRepresentation
bin1001000111110000101…
…10000100101011101111
31002221221200020222121211
410203320112010223233
520113322432244411
6355550443135251
731433306405041
oct4437026045357
91087850228554
10313404181231
11110a06543029
12508a6514527
1323727b770ab
141125143da91
15824434d221
hex48f8584aef

313404181231 has 2 divisors, whose sum is σ = 313404181232. Its totient is φ = 313404181230.

The previous prime is 313404181213. The next prime is 313404181289. The reversal of 313404181231 is 132181404313.

Together with previous prime (313404181213) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 313404181231 - 223 = 313395792623 is a prime.

It is a super-3 number, since 3×3134041812313 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 313404181193 and 313404181202.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (313404181201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156702090615 + 156702090616.

It is an arithmetic number, because the mean of its divisors is an integer number (156702090616).

Almost surely, 2313404181231 is an apocalyptic number.

313404181231 is a deficient number, since it is larger than the sum of its proper divisors (1).

313404181231 is an equidigital number, since it uses as much as digits as its factorization.

313404181231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 31.

Adding to 313404181231 its reverse (132181404313), we get a palindrome (445585585544).

The spelling of 313404181231 in words is "three hundred thirteen billion, four hundred four million, one hundred eighty-one thousand, two hundred thirty-one".