3134100113 has 4 divisors (see below), whose sum is σ = 3134661348. Its totient is φ = 3133538880.

The previous prime is 3134100089. The next prime is 3134100131. The reversal of 3134100113 is 3110014313.

3134100113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2579827264 + 554272849 = 50792^2 + 23543^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3134100113 is a prime.

It is a super-2 number, since 2×3134100113² = 19645167036613225538, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3134100091 and 3134100100.

It is not an unprimeable number, because it can be changed into a prime (3134100413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 272156 + ... + 283437.

It is an arithmetic number, because the mean of its divisors is an integer number (783665337).

Almost surely, 2^3134100113 is an apocalyptic number.

It is an amenable number.

3134100113 is a deficient number, since it is larger than the sum of its proper divisors (561235).

3134100113 is an equidigital number, since it uses as much as digits as its factorization.

3134100113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 561234.

The product of its (nonzero) digits is 108, while the sum is 17.

The square root of 3134100113 is about 55983.0341532147. The cubic root of 3134100113 is about 1463.4266346985.

Adding to 3134100113 its reverse (3110014313), we get a palindrome (6244114426).

The spelling of 3134100113 in words is "three billion, one hundred thirty-four million, one hundred thousand, one hundred thirteen".