313411433 has 2 divisors, whose sum is σ = 313411434. Its totient is φ = 313411432.

The previous prime is 313411379. The next prime is 313411451. The reversal of 313411433 is 334114313.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 267551449 + 45859984 = 16357^2 + 6772^2 .

It is a cyclic number.

It is not a de Polignac number, because 313411433 - 2²⁶ = 246302569 is a prime.

It is a super-2 number, since 2×313411433² = 196453452670226978, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 313411399 and 313411408.

It is not a weakly prime, because it can be changed into another prime (313411493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156705716 + 156705717.

It is an arithmetic number, because the mean of its divisors is an integer number (156705717).

Almost surely, 2^313411433 is an apocalyptic number.

It is an amenable number.

313411433 is a deficient number, since it is larger than the sum of its proper divisors (1).

313411433 is an equidigital number, since it uses as much as digits as its factorization.

313411433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1296, while the sum is 23.

The square root of 313411433 is about 17703.4299783968. The cubic root of 313411433 is about 679.2634997383.

Adding to 313411433 its reverse (334114313), we get a palindrome (647525746).

The spelling of 313411433 in words is "three hundred thirteen million, four hundred eleven thousand, four hundred thirty-three".