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313422414001 is a prime number
BaseRepresentation
bin1001000111110010110…
…11101000000010110001
31002221222221120022021121
410203321123220002301
520113342114222001
6355552334022241
731433620363564
oct4437133500261
91087887508247
10313422414001
11110a15866634
12508b0647981
132372b88c008
1411253a284db
158245c506a1
hex48f96e80b1

313422414001 has 2 divisors, whose sum is σ = 313422414002. Its totient is φ = 313422414000.

The previous prime is 313422413999. The next prime is 313422414031. The reversal of 313422414001 is 100414224313.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 312565973776 + 856440225 = 559076^2 + 29265^2 .

It is a cyclic number.

It is not a de Polignac number, because 313422414001 - 21 = 313422413999 is a prime.

It is a super-3 number, since 3×3134224140013 (a number of 35 digits) contains 333 as substring.

Together with 313422413999, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (313422414031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156711207000 + 156711207001.

It is an arithmetic number, because the mean of its divisors is an integer number (156711207001).

Almost surely, 2313422414001 is an apocalyptic number.

It is an amenable number.

313422414001 is a deficient number, since it is larger than the sum of its proper divisors (1).

313422414001 is an equidigital number, since it uses as much as digits as its factorization.

313422414001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 313422414001 its reverse (100414224313), we get a palindrome (413836638314).

The spelling of 313422414001 in words is "three hundred thirteen billion, four hundred twenty-two million, four hundred fourteen thousand, one".