Base | Representation |
---|---|
bin | 100011101000100001101010… |
… | …0011010111110011001111011 |
3 | 1112002202220121110022011212111 |
4 | 1013101003110122332121323 |
5 | 312040241440342442133 |
6 | 3030341102125353151 |
7 | 123006536224136263 |
oct | 10721032432763173 |
9 | 1462686543264774 |
10 | 313433097234043 |
11 | 909622592283a6 |
12 | 2b1a15261087b7 |
13 | 105b77ca660707 |
14 | 57583585427a3 |
15 | 26381aa3b71cd |
hex | 11d10d46be67b |
313433097234043 has 2 divisors, whose sum is σ = 313433097234044. Its totient is φ = 313433097234042.
The previous prime is 313433097234017. The next prime is 313433097234071. The reversal of 313433097234043 is 340432790334313.
It is a weak prime.
It is an emirp because it is prime and its reverse (340432790334313) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 313433097234043 - 245 = 278248725145211 is a prime.
It is not a weakly prime, because it can be changed into another prime (313433097234743) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156716548617021 + 156716548617022.
It is an arithmetic number, because the mean of its divisors is an integer number (156716548617022).
Almost surely, 2313433097234043 is an apocalyptic number.
313433097234043 is a deficient number, since it is larger than the sum of its proper divisors (1).
313433097234043 is an equidigital number, since it uses as much as digits as its factorization.
313433097234043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5878656, while the sum is 49.
The spelling of 313433097234043 in words is "three hundred thirteen trillion, four hundred thirty-three billion, ninety-seven million, two hundred thirty-four thousand, forty-three".
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