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313433097234017 is a prime number
BaseRepresentation
bin100011101000100001101010…
…0011010111110011001100001
31112002202220121110022011211112
41013101003110122332121201
5312040241440342442032
63030341102125353105
7123006536224136225
oct10721032432763141
91462686543264745
10313433097234017
1190962259228382
122b1a1526108795
13105b77ca6606b7
145758358542785
1526381aa3b71b2
hex11d10d46be661

313433097234017 has 2 divisors, whose sum is σ = 313433097234018. Its totient is φ = 313433097234016.

The previous prime is 313433097233947. The next prime is 313433097234043. The reversal of 313433097234017 is 710432790334313.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 261255531886801 + 52177565347216 = 16163401^2 + 7223404^2 .

It is a cyclic number.

It is not a de Polignac number, because 313433097234017 - 210 = 313433097232993 is a prime.

It is not a weakly prime, because it can be changed into another prime (313433097234217) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156716548617008 + 156716548617009.

It is an arithmetic number, because the mean of its divisors is an integer number (156716548617009).

Almost surely, 2313433097234017 is an apocalyptic number.

It is an amenable number.

313433097234017 is a deficient number, since it is larger than the sum of its proper divisors (1).

313433097234017 is an equidigital number, since it uses as much as digits as its factorization.

313433097234017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3429216, while the sum is 50.

The spelling of 313433097234017 in words is "three hundred thirteen trillion, four hundred thirty-three billion, ninety-seven million, two hundred thirty-four thousand, seventeen".