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313433114011273 is a prime number
BaseRepresentation
bin100011101000100001101010…
…1011010111110011010001001
31112002202220122121212112220101
41013101003111122332122021
5312040242004141330043
63030341103525125401
7123006536516553424
oct10721032532763211
91462686577775811
10313433114011273
1190962267747383
122b1a152b859861
13105b7800c85c79
14575835a86c9bb
1526381abacd24d
hex11d10d56be689

313433114011273 has 2 divisors, whose sum is σ = 313433114011274. Its totient is φ = 313433114011272.

The previous prime is 313433114011223. The next prime is 313433114011301. The reversal of 313433114011273 is 372110411334313.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 208561341372409 + 104871772638864 = 14441653^2 + 10240692^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-313433114011273 is a prime.

It is not a weakly prime, because it can be changed into another prime (313433114011223) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156716557005636 + 156716557005637.

It is an arithmetic number, because the mean of its divisors is an integer number (156716557005637).

Almost surely, 2313433114011273 is an apocalyptic number.

It is an amenable number.

313433114011273 is a deficient number, since it is larger than the sum of its proper divisors (1).

313433114011273 is an equidigital number, since it uses as much as digits as its factorization.

313433114011273 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54432, while the sum is 37.

Adding to 313433114011273 its reverse (372110411334313), we get a palindrome (685543525345586).

The spelling of 313433114011273 in words is "three hundred thirteen trillion, four hundred thirty-three billion, one hundred fourteen million, eleven thousand, two hundred seventy-three".