Base | Representation |
---|---|
bin | 100011101000100001101010… |
… | …1011010111110011001010111 |
3 | 1112002202220122121212112211112 |
4 | 1013101003111122332121113 |
5 | 312040242004141324343 |
6 | 3030341103525125235 |
7 | 123006536516553323 |
oct | 10721032532763127 |
9 | 1462686577775745 |
10 | 313433114011223 |
11 | 90962267747338 |
12 | 2b1a152b85981b |
13 | 105b7800c85c3b |
14 | 575835a86c983 |
15 | 26381abacd218 |
hex | 11d10d56be657 |
313433114011223 has 2 divisors, whose sum is σ = 313433114011224. Its totient is φ = 313433114011222.
The previous prime is 313433114011141. The next prime is 313433114011273. The reversal of 313433114011223 is 322110411334313.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 313433114011223 - 232 = 313428819043927 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 313433114011223.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (313433114011273) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156716557005611 + 156716557005612.
It is an arithmetic number, because the mean of its divisors is an integer number (156716557005612).
Almost surely, 2313433114011223 is an apocalyptic number.
313433114011223 is a deficient number, since it is larger than the sum of its proper divisors (1).
313433114011223 is an equidigital number, since it uses as much as digits as its factorization.
313433114011223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 32.
Adding to 313433114011223 its reverse (322110411334313), we get a palindrome (635543525345536).
The spelling of 313433114011223 in words is "three hundred thirteen trillion, four hundred thirty-three billion, one hundred fourteen million, eleven thousand, two hundred twenty-three".
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