Base | Representation |
---|---|
bin | 100011101000100001101010… |
… | …1011010111110011010101101 |
3 | 1112002202220122121212112221201 |
4 | 1013101003111122332122231 |
5 | 312040242004141330214 |
6 | 3030341103525125501 |
7 | 123006536516553505 |
oct | 10721032532763255 |
9 | 1462686577775851 |
10 | 313433114011309 |
11 | 90962267747406 |
12 | 2b1a152b859891 |
13 | 105b7800c85ca6 |
14 | 575835a86ca05 |
15 | 26381abacd274 |
hex | 11d10d56be6ad |
313433114011309 has 2 divisors, whose sum is σ = 313433114011310. Its totient is φ = 313433114011308.
The previous prime is 313433114011301. The next prime is 313433114011319. The reversal of 313433114011309 is 903110411334313.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 308044726747209 + 5388387264100 = 17551203^2 + 2321290^2 .
It is a cyclic number.
It is not a de Polignac number, because 313433114011309 - 23 = 313433114011301 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (313433114011301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156716557005654 + 156716557005655.
It is an arithmetic number, because the mean of its divisors is an integer number (156716557005655).
Almost surely, 2313433114011309 is an apocalyptic number.
It is an amenable number.
313433114011309 is a deficient number, since it is larger than the sum of its proper divisors (1).
313433114011309 is an equidigital number, since it uses as much as digits as its factorization.
313433114011309 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 34992, while the sum is 37.
The spelling of 313433114011309 in words is "three hundred thirteen trillion, four hundred thirty-three billion, one hundred fourteen million, eleven thousand, three hundred nine".
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