Base | Representation |
---|---|
bin | 1110010000001111100000… |
… | …00000011111100101100011 |
3 | 11002222111101100011100100102 |
4 | 13020013300000133211203 |
5 | 13102021314133121011 |
6 | 150355230413413015 |
7 | 6413362345456025 |
oct | 710076000374543 |
9 | 132874340140312 |
10 | 31344403020131 |
11 | 9a950a53a34a3 |
12 | 362290919a16b |
13 | 14649c28687a6 |
14 | 7a5111ba6015 |
15 | 39551701973b |
hex | 1c81f001f963 |
31344403020131 has 2 divisors, whose sum is σ = 31344403020132. Its totient is φ = 31344403020130.
The previous prime is 31344403020043. The next prime is 31344403020149. The reversal of 31344403020131 is 13102030444313.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 31344403020131 - 210 = 31344403019107 is a prime.
It is a super-2 number, since 2×313444030201312 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 31344403020094 and 31344403020103.
It is not a weakly prime, because it can be changed into another prime (31344403020331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15672201510065 + 15672201510066.
It is an arithmetic number, because the mean of its divisors is an integer number (15672201510066).
Almost surely, 231344403020131 is an apocalyptic number.
31344403020131 is a deficient number, since it is larger than the sum of its proper divisors (1).
31344403020131 is an equidigital number, since it uses as much as digits as its factorization.
31344403020131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10368, while the sum is 29.
Adding to 31344403020131 its reverse (13102030444313), we get a palindrome (44446433464444).
The spelling of 31344403020131 in words is "thirty-one trillion, three hundred forty-four billion, four hundred three million, twenty thousand, one hundred thirty-one".
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