313502504234153 has 4 divisors (see below), whose sum is σ = 337618081482948. Its totient is φ = 289386926985360.

The previous prime is 313502504234141. The next prime is 313502504234191. The reversal of 313502504234153 is 351432405205313.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 63382807214224 + 250119697019929 = 7961332^2 + 15815173^2 .

It is a cyclic number.

It is not a de Polignac number, because 313502504234153 - 2⁶ = 313502504234089 is a prime.

It is a super-2 number, since 2×313502504234153² (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 313502504234153.

It is not an unprimeable number, because it can be changed into a prime (313502504234053) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12057788624378 + ... + 12057788624403.

It is an arithmetic number, because the mean of its divisors is an integer number (84404520370737).

Almost surely, 2^{313502504234153} is an apocalyptic number.

It is an amenable number.

313502504234153 is a deficient number, since it is larger than the sum of its proper divisors (24115577248795).

313502504234153 is a wasteful number, since it uses less digits than its factorization.

313502504234153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24115577248794.

The product of its (nonzero) digits is 648000, while the sum is 41.

Adding to 313502504234153 its reverse (351432405205313), we get a palindrome (664934909439466).

The spelling of 313502504234153 in words is "three hundred thirteen trillion, five hundred two billion, five hundred four million, two hundred thirty-four thousand, one hundred fifty-three".